First of all, I want to remind that in the Soviet school we were taught that there is a difference between a multiplication with signed and unsigned. The difference is that the multiplication of the unsigned work is considered as a single value. At the household level, if 2A is a quart of water, 2×and two half liters of fluid.

Consider this example:

2A:2A=1

at a=1+2

2(1+2):2(1+2)=

**6:2(1+2)**=6:6=

**1**For those who do not remember this rule, I propose to solve an example for understanding:

This example of a "collection of problems in algebra", Part I, grades 6-7. (P. A. Larichev)

On the Internet you can download it for free and see in my right.

Based on the above

**6:2(1+2)=1****Here's what else I found recently:**In the manual for the mathematical faculties of pedagogical institutes in the course of teaching mathematics, which

** was taught by our faculty of algebra** at pedagogical Universities of the Soviet Union, stated unequivocally that in algebra the multiplication sign between the components of the action are stronger than the division sign. And the fact that in the disputed example, the multiplication sign is omitted, says that

**a controversial example of algebraic**.

With the following link You can download:

Methods of teaching algebra, a Course of lectures, Shuster M. F., 1967.

\r

https://russianclassicalschool.ru/biblioteka/matem...Me applied text on the 43rd page of the manual.

So, for those who are well studied in the Soviet school

**6:2(1+2) = 1**